Ok, I've figured it out. I apoligze for all the messages, if someone
has a better way to do it, please let me know. Here is what I did
I made a vector with the three equations (l is 34)
[-578=p*0^2+q*0+r 289=p*(l/2)^2+q*(l/2)+r -578=p*l^2+q*l+r]
then I made another vector
[p q r]
then I used s.solv, and SOLVE.
This generated the values I was looking for,
p=-3468/l^2 q=3468/l and r=578
Thank you and sorry again about all the messages.
--- In 50g@yahoogroups.com, "renystro" <renystro@...> wrote:
>
> Obviously forgot to give you these...apologies for all the messages.
> M1=-578
> M2=289
> M3=-578
>
> --- In 50g@yahoogroups.com, "renystro" <renystro@> wrote:
> >
> > I am trying to solve three simultaneous equations and I can't
seem
Show quoted textHide quoted text
> to
> > figure out how to do it. I've gone through the manual and keep
> > getting an error trying to use msolv
> >
> > I have
> > M1=p*0^2+q*0+r
> > M2=p*(L/2)^2+q*(L/2)+r
> > M3=p*L^2+q*L+r
> >
> > The answers are p=-3 q=102 and r=-578
> >
> > Can anyone give me the syntax to get this from a 50g?
> >
> > I've also tried entering them as vectors and then using solve but
> it
> > only gave me the trivial solution (0 0 0)
> >
> > Thank you.
> >
>