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Re: Complex Roots

2009-01-03 by Don Hart

Also note that if you've set the 'exact' mode, the
solution to x^2+1=0 will give the results in an algebraic
form.

And you don't have to have the '=0' part. I put it in to
make it easier to see what's going on.

--- In 50g@yahoogroups.com, "Joe Colannino"
<joecolannino@...> wrote:
>
> Don, that was really helpful. It will be easy enough
to write a program to
> do this automatically. When I do so, I'll share it
with the group. Thanks
> again!
>
>
>
> Joe
>
>
>
> _____
>
> From: 50g@yahoogroups.com [mailto:50g@
yahoogroups.com] On Behalf Of Don Hart
> Sent: Wednesday, December 31, 2008 10:56 PM
> To: 50g@yahoogroups.com
> Subject: Re: [50g] Complex Roots
>
>
>
> Make sure you're in complex & approx modes, then
SOLVEX the equation x^3 + 1
> = 0
>
> For the other case, SOLVEX the equation x^3-2-11*i=0
>
> --- On Wed, 12/31/08, joecolannino <joecolannino@
> <mailto:joecolannino%40sbcglobal.net> sbcglobal.net>
wrote:
>
> > From: joecolannino <joecolannino@
<mailto:joecolannino%40sbcglobal.net>
> sbcglobal.net>
> > Subject: [50g] Complex Roots
> > To: 50g@yahoogroups. <mailto:50g%40yahoogroups.com>
com
> > Date: Wednesday, December 31, 2008, 1:15 PM
> > Does anyone have a program written for the HP 50G
that will
> > give all
> > complex roots of a number? For example,the cube
roots of
> > -1 are
> > {[1+sqrt(3)]/2, -1, and [1-sqrt(3)]/2 } but the HP
50G
> > will give only
> > the first. Trying to evaluate the cube root of
2+11i it
> > chokes
> > altogether though the answers are clearly {2+i,
> > -1.866+1.232i
> > (approx), -0.1340-2.232i (approx)}.
> >
> > Joe
>

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