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RE: [50g] Complex Roots

2009-01-01 by Joe Colannino

Don, that was really helpful.  It will be easy enough to write a program to
do this automatically.  When I do so, I'll share it with the group.  Thanks
again!

 

Joe

 

  _____  

From: 50g@yahoogroups.com [mailto:50g@yahoogroups.com] On Behalf Of Don Hart
Sent: Wednesday, December 31, 2008 10:56 PM
To: 50g@yahoogroups.com
Subject: Re: [50g] Complex Roots

 

Make sure you're in complex & approx modes, then SOLVEX the equation x^3 + 1
= 0

For the other case, SOLVEX the equation x^3-2-11*i=0

--- On Wed, 12/31/08, joecolannino <joecolannino@
<mailto:joecolannino%40sbcglobal.net> sbcglobal.net> wrote:

> From: joecolannino <joecolannino@ <mailto:joecolannino%40sbcglobal.net>
sbcglobal.net>
> Subject: [50g] Complex Roots
> To: 50g@yahoogroups. <mailto:50g%40yahoogroups.com> com
> Date: Wednesday, December 31, 2008, 1:15 PM
> Does anyone have a program written for the HP 50G that will
> give all
> complex roots of a number? For example,the cube roots of
> -1 are
> {[1+sqrt(3)]/2, -1, and [1-sqrt(3)]/2 } but the HP 50G
> will give only
> the first. Trying to evaluate the cube root of 2+11i it
> chokes
> altogether though the answers are clearly {2+i,
> -1.866+1.232i
> (approx), -0.1340-2.232i (approx)}. 
> 
> Joe

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