50g

--- In 50g@yahoogroups.com, "Juan C." <jcbuchin@...> wrote:

>
>
>
> Hello there, I posted your second question in hp forums, and there

is

> not an easy solution to that problem. Giancarlo Mattioni suggested

this:

>
> " If you don't mind, I'd point you to a comp.sys.hp48 thread (not

that

> recent...):
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>

http://groups.google.com/group/comp.sys.hp48/browse_frm/thread/375e15
669\

> 9e66
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> 951/ebc3964b576b5bc1?hl=it&lnk=gst&q=whole+graph#ebc3964b576b5bc1
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>
>
>
>
>

<http://groups.google.com/group/comp.sys.hp48/browse_frm/thread/375e1
566\

> 99e66951/ebc3964b576b5bc1?

hl=it&lnk=gst&q=whole+graph#ebc3964b576b5bc1>

>
> In summary, the "other half" of the graph can't be showed as it

is "made

> of" complex values for negative x values.
>
>
>
>
> I think you can catch the picture you want if you try to graph:
>
> Y1(X)=|X^(5/3)| "
>
>
> Thanks again. Much appreciated!
>
> So I tried the IFTE function like this: IFTE(X>0,X^(5/3),-ABS(X^

(5/3))),

> it isn't an elegant solution but it works.
>