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Subject: RE: [motm] Different ring mod sounds

From: Dan Higdon <hdan@...>
Date: 2000-11-10

RE: [motm] Different ring mod sounds

AFAIK, no.  At least not for signals represented as voltage levels over time (as opposed to frequencies).  4QM is just like "normal" arithmetic multiplication, with neg ∗ neg = pos, and neg ∗ pos = neg.  2Q multiplication forces the modulator to always be positive.  Now, I don't know if it does this through full-wave rectification (same as absolute value), or half-wave (same as the function "max (x, 0)").  I suspect half-wave, since that's essentially how a linear vca works.

So for the mathematically inclined, the output voltages are:
4QM (modulator, carrier) = modulator ∗ carrier
2QM (modulator, carrier) = max (modulator,0) ∗ carrier

-hdan

-----Original Message-----
From: jwbarlow@... [mailto:jwbarlow@...]
Sent: Thursday, November 09, 2000 9:17 PM
To: motm@egroups.com
Subject: Re: [motm] Different ring mod sounds


Thanks JH for the detailed thoughts on RM (which I will be digesting for a
while)!

Now another stoopid question, is 4Q multiplication the same as cross product
multiplication and 2Q the same as dot product multiplication?

JB

In a message dated 11/9/2000 7:16:11 AM, synth1@... writes:

>The sidebands
>produced are not
>the same as a 4-quadrant multiplier, because of the "sign" of the signals
>(+
>and - values) are
>"computed" differently.
>

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