I believe Paul is referring to an op-amp configured with 1/.98 "gain". If
you're really concerned about accuracy (or you're using 5% resistors), you
can add a little "tuning" potentiometer.
It should just require a few resistors and half a dual op-amp. I suggest
you try this method (via active electronics) instead of a passive
component method.
Andrew
-| Andrew Schrock |
aschrock@... |-
On Wed, 3 Nov 1999, Cary Roberts wrote:
> I don't see why I need gain. A MIDI to CV converter (ala MPU101) can
> only spit out 1v/oct. That means the Multimoog which has a response
> of .98v/oct would be sharp when played from a 1v/oct source. Right?
> If this is correct, what type of resistor network do I need to come
> up with that will give me a very tight tolerance? A simple votage
> divider probably won't be accurate enough. Any suggestions?
>
> -Cary
>
>
> >From: "Paul Schreiber" <synth1@...>
> >
> >Because you need ∗gain∗ to go "that direction". The gain needed is 1/.98
> >
> >Paul S.
> >
> >>From: Cary Roberts <Cary.Roberts@...>
> >>
> >>Since I'm no longer on DIY, can anyone suggest another way to accomplish
> >>1v/oct to .98v/oct conversion besides:
> >>
> >>http://machines.hyperreal.org/manufacturers/Moog/schematics/moogfix.jpg
> >>
> >>I was thinking of a voltage divider network, but I don't think I could
> >>get resistors of high enough tolerance. Any other ideas?
> >>
> >>-Cary
>
> >