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Envelator Mix module logic and quadrature mode

2002-04-19 by grantrichter2001

OK, one of the original functions of the SQR output on the 
Envelator was to act as mono-stable for making a gated ADSR 
envelope. That is if you have two Envelator modules, you can set 
up one as an ADSR and another as a monstable, this will give 
you a fixed gate time and allow you to "loop" an ADSR with the 
end pulse.

The polarity is wrong for using it in quadrature mode, SQR goes 
high and stays high as long as the Envelator is in the Attack 
portion of the envelope. For quadrature, you need the inverse.

You can use the cossfader on the bottom as a logic inverter to 
get the correct polarity. Here is how:

1. Put a dummy plug into the Mix2 input (disconnect Env 2 output)
2. Route a +10 volt signal to the Mix 1 input (a joystick all the way 
up will work)
3. Route the Env 1 SQR signal to the Mix Mod input (mixture 
modulation)
4. Set the MixMod control to max and Mix control to min
5. Route the Mix output to the gate input of Env 2

Now Env 2 will start it's attack phase as soon as Env 1 
completes it's attack phase, also called quadrature mode. Route 
Env 2 END pulse to Env 1 GATE input to make a quadrature LFO.

How does it work? When MixMod is at zero volts, Mix1 is routed to 
the Mix ouput, and it is at +10 volts. When MixMod is at +10 volts it 
is routing Mix2 to the Mix output, which is at zero volts - hence an 
inverter.

If you think about it, the Mix section on the Envelator can be used 
for logic functions, AND would be MixMod at +10 AND Mix2 at 
+10, otherwise the output is zero.

The input thresholds of gate inputs on the system are set to +1.5 
volts so you can interface to +5 volts systems like Kenton and 
Roland rhythm boxes. So with the MIX control set to the center, 
with +10 volts at Mix1 OR Mix2, +5 volts will be output from the 
MIX output. Because the gate threshold is at +1.5 volts, it will 
behave like an OR gate.

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