MOTM

oooops, my mistake. -nate

Paul Schreiber wrote:

> Sure, 30-40 seconds easy!
>
> Paul S.
>
>
> ----- Original Message -----
> From: "Nathan Alan Hunsicker" <nate@...>
> To: <motm@egroups.com>
> Sent: Tuesday, June 20, 2000 5:35 PM
> Subject: Re: [motm] lag processor question...
>
>
> > and if remember correctly, i don't think the 820 lag has a lag time
> as
> > high as 30 seconds. I think it was around 5 sec or shorter. -Nate
> >
> > jwbarlow@... wrote:
> >
> > > Damn! This patch won't work in the way I described since the 820
> > > appears to
> > > have no HOLD input (a gate input which holds the output constant
> > > regardless
> > > of the input). You'd have to have another S/H in front of the VC
> LAG
> > > input in
> > > order to keep the input from changing (and the output slowly
> following
> > > that
> > > input).
> > >
> > > Now it's getting expensive!
> > > JB
> > >
> > > In a message dated 6/20/2000 1:27:38 PM, jwbarlow@... writes:
> > >
> > > >Now another idea for the 820 LAG PROCESSOR module:
> > > >1) Take a CV source to the input of the 820 (e.g., noise).
> > > >2) Take the 820 output to the input of the 100 (or 101) S/H.
> > > >3) Take the 100 output to a CV input (say a 1v/oct of an
> oscillator).
> > >
> > > >4) Set the lag time to be rather long (like say a 5 octave sweep
> in
> > > thirty
> > > >
> > > >seconds).
> > > >5) Set the S/H level all the way up.
> > > >
> > > >This great patch (which I learned from the old Serge manual)
> keeps
> > > step
> > > >size
> > > >small but allows for a full 10V peak to peak swing for the total
> > > voltage
> > > >
> > > >output over time. This means that (in the patch example given
> above)
> > > any
> > > >two
> > > >adjacent notes must be close together, but over time a full ten
> > > octaves
> > > >would
> > > >be covered.
> > >
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