>>I'm not sure if you're asking about the rectifier or the envelope follower, so I'll just answer both. Just feed the same signal into both the X and Y inputs on the ring mod and you'll get a rectified signal out since when the signal is positive, the two positives multiply to give you a positive out, and when the signal goes negative, the two negatives multiply and also give you a positive output.<< That doesn't sound right. Squaring a signal (i.e. multiplying it by itself) doesn't rectify it, in the general case. Consider a sine wave as an input signal. There is a trigonometric identity as follows: sin^2(x) = 1/2 (1 - cos(2x)) for all values of x [where "^2" represents raising to the second power in ASCII]. A cosine wave is merely a sine wave shifted ninety degrees, so your output is a sine wave of twice the frequency (because of the 2 in front of the x)and half the amplitude (because of the 1/2 at the beginning) of the input, with positive-only DC bias (because of the subtraction from 1). That's not a rectified sine wave. --Adam
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RE: [motm] Emulating Modules MOTM Doesn't Provide
2008-05-07 by Adam Schabtach
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