MOTM

Well, I'm not sure what Brian Eno has to do with this.  I have dozens
of his records, and I've never heard him do anything vaguely similar
to imitative synthesis.  Perhaps I'm missing something.

Anyway, while I know that some people are into imitative synthesis,
and I can see how it's interesting and challenging, it simply isn't
practical.  As someone already pointed out, using sampling or
physical modeling is easier and less expensive.

A far as EQ is concerned, there are several issues:

EQ cannot produced inharmonics, it can only change the amplitude of
frequencies that are already present.

The resonance or frequency response produced by the body of an
acoustic instrument, as well as the room it is in, while often very
complex, does not vary with the pitch of the note played.

While I do not now of any "1v/Oct" EQ's there are numerous digital
EQ's on the market that can save and recall settings.  There are also
EQ's that can respond to the dynamics of a signal.


On 4/20/07, rogerpellegrini put forth:
>--- In motm@yahoogroups.com, jneilyahoo@... wrote:
>  >(Brian Eno:)It's actually being used rather like a graphic
>equalizer. I do have two graphics
>  > as well, which I use. Those I should have mentioned first,
>because they are really the most important. I can't
>  > understand why nobody has built a synthesizer with a graphic built into it.
>  >
>
>I couldn't agree more!  Standard subtractive synthesis has nearly
>always been done in a crude way - with one filter.  It's like doing
>surgery wearing oven mitts.  It's a big reason why analog synths and
>even VA's have a "sound" - a desired sound, yes, but a sonic
>signature that's unmistakable across manufacturers and models.  In
>my opinion, it's a travesty that the one instrument that should have
>the most sophisticated EQ has none!
>
>How about a digital motm module with say 8 adjustable bands,
>excessive boost/cut, adjustable Q, with parallel shift of band
>frequencies under 1v/octave control?  Storage/recall of all
>settings, too?  What do you think?