Oops! I think dat wrong. It's been a long time, but we need RMS first, right? So, 10V peak to peak is 5V peak, then 5V x .7071 (square root of 2 over 2) = 3.536V RMS dBu = 20log(V1/V2) where V2 = .775V 20log(3.536/.775)= 13.18 dBu Barry S. --- In motm@yahoogroups.com, "coyoteous" <antithesist@...> wrote: > > --- In motm@yahoogroups.com, "Paul Schreiber" <synth1@> wrote: > > > > MOTM uses very large signals on the outputs: 10V pk-pk which is something like > > +24dBu > > 22.22 dBu reference: 0.775 V > 20.00 dBV reference: 1 V > 22.22 dBm reference: 1 mW at 600 ohms
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Re: How to connect balanced signals to the MOTM
2006-03-31 by coyoteous