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Re: Off-topic - 1v/oct to .98v/oct conversion

1999-11-03 by Andrew Schrock

I believe Paul is referring to an op-amp configured with 1/.98 "gain". If
you're really concerned about accuracy (or you're using 5% resistors), you
can add a little "tuning" potentiometer. 

It should just require a few resistors and half a dual op-amp. I suggest
you try this method (via active electronics) instead of a passive
component method. 

Andrew

-| Andrew Schrock | aschrock@... |-

On Wed, 3 Nov 1999, Cary Roberts wrote:
> I don't see why I need gain.  A MIDI to CV converter (ala MPU101) can
> only spit out 1v/oct.  That means the Multimoog which has a response
> of .98v/oct would be sharp when played from a 1v/oct source.  Right?
> If this is correct, what type of resistor network do I need to come
> up with that will give me a very tight tolerance?  A simple votage
> divider probably won't be accurate enough.  Any suggestions?
> 
> -Cary
> 
> 
> >From: "Paul Schreiber" <synth1@...>
> >
> >Because you need *gain* to go "that direction". The gain needed is 1/.98
> >
> >Paul S.
> >
> >>From: Cary Roberts <Cary.Roberts@...>
> >>
> >>Since I'm no longer on DIY, can anyone suggest another way to accomplish
> >>1v/oct to .98v/oct conversion besides:
> >>
> >>http://machines.hyperreal.org/manufacturers/Moog/schematics/moogfix.jpg
> >>
> >>I was thinking of a voltage divider network, but I don't think I could
> >>get resistors of high enough tolerance.  Any other ideas?
> >>
> >>-Cary
> 
> >

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