I believe Paul is referring to an op-amp configured with 1/.98 "gain". If you're really concerned about accuracy (or you're using 5% resistors), you can add a little "tuning" potentiometer. It should just require a few resistors and half a dual op-amp. I suggest you try this method (via active electronics) instead of a passive component method. Andrew -| Andrew Schrock | aschrock@... |- On Wed, 3 Nov 1999, Cary Roberts wrote: > I don't see why I need gain. A MIDI to CV converter (ala MPU101) can > only spit out 1v/oct. That means the Multimoog which has a response > of .98v/oct would be sharp when played from a 1v/oct source. Right? > If this is correct, what type of resistor network do I need to come > up with that will give me a very tight tolerance? A simple votage > divider probably won't be accurate enough. Any suggestions? > > -Cary > > > >From: "Paul Schreiber" <synth1@...> > > > >Because you need *gain* to go "that direction". The gain needed is 1/.98 > > > >Paul S. > > > >>From: Cary Roberts <Cary.Roberts@...> > >> > >>Since I'm no longer on DIY, can anyone suggest another way to accomplish > >>1v/oct to .98v/oct conversion besides: > >> > >>http://machines.hyperreal.org/manufacturers/Moog/schematics/moogfix.jpg > >> > >>I was thinking of a voltage divider network, but I don't think I could > >>get resistors of high enough tolerance. Any other ideas? > >> > >>-Cary > > >
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Re: Off-topic - 1v/oct to .98v/oct conversion
1999-11-03 by Andrew Schrock
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