MOTM

On Sun, 31 Oct 1999, The Old Crow wrote:

>   You have some input rate and want to create, say, 3 output pulses for
> every 5 input pulses.  A ratio multipler will take the input rate,
> multiply it by 5, then divide it by 3 and present the new rate on an
> output.

  Er, I didn't pay attention here.  3 outs for 5 ins multiplies by 3 and
divides by 5.

   out = in x (M / N), above example M=3, N=5

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