If you look at the transistor from the front, facing the flat side, the leads are Emitter Base Collector left-to-right. Paul S. -----Original Message----- From: Dave Bradley <daveb@...> To: motm@onelist.com <motm@onelist.com> Date: Monday, July 19, 1999 1:23 PM Subject: RE: [motm] MOTM-800 ADSR Mod >From: "Dave Bradley" <daveb@...> > >> I looked through the archives for the mod to give the 800 full ADSR with >> only a gate signal, >> but only came across the jumper wire from the Q1 collector method. >> >> There was also mention of using a 5k resistor. > >That's the one. I just used a jumper, with no problems. Others have stuck a >5K resistor in the line due to paranoia about potential transients or shorts >when plugging / unplugging a trigger input. > >I attached my wire not to the Q1 collector but to the top of the board at >the nearest resistor connected directly to the collector (schematics are at >home, so I don't know which resistor). I then cable tied the extra wire to >one of the bundles going to the jack. > >> Which side would the collector of Q1 be? > >The collector pin can be deciphered from the schematic. The lead that >connects perpendicularly to the vertical line in the transistor symbol is >usually drawn from the left, and is the BASE. The lead that emanates from >the vertical line at an angle with an arrowhead is the EMITTER. The other >lead emanating at an angle without any arrow is the COLLECTOR. > >Dave Bradley >Principal Software Engineer >Engineering Animation, Inc. >daveb@... > > >--------------------------- ONElist Sponsor ---------------------------- > >Congratulations MilitaryEFM. Our latest ONElist of the week. >http://www.onelist.com >How is ONElist changing YOUR life? Visit our homepage and let us know! > >------------------------------------------------------------------------ >
Message
Re: MOTM-800 ADSR Mod
1999-07-19 by Paul Schreiber
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