Thanks, Peter - I think I understand the function now, but I also still think your graph is
wrong. I believe it should be a verically flipped version of the first graph, rather than
horizontally flipped as you have it. 0v in = 8v out, right? Check it out.
- Barry
http://ancientsun.blogspot.com
Cosmic Debris "On the Shores of a Different Time" CD with Richard Bugg coming soon!
--- In PLAN_B_analog_blog@yahoogroups.com, "(i think you can figure that out)"
<peter@...> wrote:
>
> barry said:
>
> looks like that voltage mirror thingy does time reversal, too! (according to
> the graph) ;-)
>
> http://www.ear-group.net/model_26.html
>
> - Barry
>
> Looks as if it does, doesn't it? If it did however, I'd be making a lot more $$ for the
> Military!
>
> The resting state of the Voltage Mirror (no input) is 8 volts positive. It sits up there with
> no input is applied to it's output. So inserting the waveshape shown in the diagram,
that's
> exactly what you'll get out. It may appear to be time reserved, but it's just phase
refersed.
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>
> A true mirror.
>
> I guess I could have called it the 'Positively Biased Voltage Inverter, but what's the fun in
> that?
>
> - P
>