Mellotronists

First time posting to this group, and wish I'd discovered it sooner.
Hoping someone can help with a question.

I have a prototype of a 16-voice sampler that I designed some years
ago that uses PCMCIA flash memory for sound storage - no disks or RAM
to load. It occured to me the other day that it might make an ideal
mellotron emulator, since it has more than enough memory to hold all
8 seconds of all 35 notes (and it's not much good for anything
else). So I went hunting for mellotron samples on the web and
discovered the Mike Pinder CD-ROM, which at first glance seemed
ideal. But after reading the description, I am concerned about
something. If my math is correct:

8 sec * 44,100 samples/sec * 2 bytes/sample * 35 notes = 24,696,000
bytes

In other words, if each note is sampled at 44.1kHz, 16-bit mono for
the full 8 seconds, then the size of the sample set should be around
25 MBytes. The CD-ROM description, however, implies that each sound
will fit into a 16 MByte bank. I think I read somewhere that a full
sound set is actually around 12 MByte. This would seem to indicate
that either the sampling rate is 22.05kHz, not 44.1kHz, or that all
35 notes are not included.

Can anyone shed some light on this?

Thanks,

-Jamie Robertson

On Tue, 26 Mar 2002, jamierob54 wrote:

> This would seem to indicate that either the sampling rate
> is 22.05kHz, not 44.1kHz, or that all 35 notes are not included.

You obviously know your maths -- the Pinder CD-ROM is indeed
22.05kHz/16 bits/35 notes.

Personally, I wish at least the 8-voice choir would have
been sampled at 44.1 kHz or higher.

-joachim