[sdiy] CEM3328 seems to only have buffers at the end

[Harry Bissell Jr]

I mean the VCF input differential pair, which imho makes the
  rest of the ladder a slave to it (current flow in the series circuit).
  
  Its almost impossible to really 'clip' the Moog ladder... it really does
  more of a compression than a true clipping.  
  
  I'm talking about the VCF alone, with no VCA involved.
  
  Contrast what your average SVF or Sallen-Key archetecture will
  do... the Moog is very 'tame'.  Your average guitarist (raises hand :^)
  would describe the action more as a limiter than a distortion.
  
  I don't think there is 'inherent feedback' in the Moog Ladder unless
  the resonance circuit is engaged.  The distortion is still there, albeit
  it is also 'filtered' like you describe.  (I'm talking global feedback)
  
  H^) harry

Antti Huovilainen <ajhuovil at cc.hut.fi> wrote:  On Mon, 20 Feb 2006, Harry Bissell Jr wrote:

> IMHO the Moog distortion is more a product of the differential
>  pair diatortion, and has very little to do with 'filter'

Do you mean the VCA differential pair(s)?

A typical Moog synth has two sources of distortion: Filter and VCA.

The filter distortion depends on the cutoff. Much below cutoff the 
inherent feedback reduces distortion, and much above cutoff the filtering 
action is so heavy as to make the harmonics inaudible. Most of the 
distortion happens near cutoff therefore.

The VCA distortion is one or more tanh in series (one for Prodigy / 
Taurus, three for Minimoog).

Antti

"No boom today. Boom tomorrow. There's always a boom tomorrow"
   -- Lt. Cmdr. Ivanova

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