--- In lpc2000@yahoogroups.com, "Sveinung Waade" <sveinung@w...>
wrote:
> Hello,
>
>
>
> Why does not the -WE for LPC2294 go active low together when the
chips select 2 (CS2) turn active low ?
>
> The PINSEL2.bit8 = 1 so the -WE signal should be activated.
>
> I have also verified that p3.27 (-WE) goes three state when
PINSEL2.bit8 = 0.
>
> If I set BCFG2_bit.WP = 1 (write protection) the Test() function
runs into a prefetch exception.
>
>
>
> void LPC2294InitExternMemory(void)
>
> {
>
> /*
>
> // Octal Uart chip select.
>
> BCFG2_bit.IDCY = 3; // 16.66nsec * (3+1) = 65 nsec.
>
> BCFG2_bit.WST1 = 15; // 15 * 16.66nsec = 249nsec wait states
for the UART
>
> BCFG2_bit.WST2 = 15; // 15 * 16.66nsec = 249nsec wait states
for the UART
>
> BCFG2_bit.RBLE = 0; // 8 Bit access BLS3:0 high during access.
>
> //BCFG2_bit.BUSERR = ; // Status bit
>
> //BCFG2_bit.WPERR = ; // Status bit
>
> BCFG2_bit.WP = 0; // Write protect off(0).
>
> BCFG2_bit.BM = 0; // Burst rom bank off(0).
>
> BCFG2_bit.MW = 0; // 8 bit(00) 16 bit(01) 32 bit(10)
reserved(11)
>
> //BCFG2_bit.AT = ; // Always zero
>
> */
>
> BCFG2 = 0x000079E3;
>
> /*
>
> PINSEL2 = BIT2| // JTAG port.
>
> BIT4| // Data[0,15]
>
> BIT8| // Enable WE
>
> BIT11| // Enable CS1
>
> BIT14| // Enable CS2
>
> BIT23| // Enable address line A0
>
> BIT24| // Enable address line A1
>
> BIT26; // Enable address line A2-A5.
>
> */
>
> PINSEL2 = 0x05804914;
>
> }
>
>
>
> BYTE testArray[10];
>
>
>
> void Test(void)
>
> {
>
> BYTE *ptr;
>
> int i;
>
> ptr = (BYTE *) 0x82000000;
>
> i = 9;
>
> while(i--) {
>
> *ptr = i;
>
> i++;
>
> i--;
>
> testArray[i] = *(ptr++);
>
> }
>
> }
>
>
>
> You have any idée what is wrong?
>
>
>
> Sveinung
>
>
>
> [Non-text portions of this message have been removed]
Sveinung
I seem to remember that with an 8 bit bus the processor uses /BLS0 as
it's write enable pin. I fell into the same trap!!!
regards
DougMessage
Re: -WE LPC 2294 won't go active low
2005-03-18 by douglasbolton
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