Cgs synth

You can't guarentee what the diode drop will be - it will vary with current.
You will also have the loading effect of the transformer coils on whatever
you are driving, and unless it is very low impedance, you will lose there too.

Ken

>Hi Ken , thanks for your reply. I should have mentioned that my soldering

iron and test equipment are in storage , so i'm not able to buid the rrm or
measure output.What other losses would you expect?Regardsgeoff

> To: cgs_synth@yahoogroups.com
>From: sasami@...
>Date: Tue, 25 Oct 2011 04:03:55 +0000
>Subject: Re: [cgs_synth] real ring modulator
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> I can't tell you what the output will be because there will also be other
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>losses in the system. It would be best to measure it.
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>Ken
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>>Hi All , have i got this right?
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>>Using the RRM as a freq. doubler , if i have a 1V p-p signal at both the
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>mod and carrier inputs and the schottky diodes each measure 250mv forward
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>voltage drop , will the ouput be 1volt p-p?
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>>Thanks in advance.
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>>Regards
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>>------------------------------------
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>>The CGS Modular Synth home page: http://www.cgs.synth.net/
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>>Yahoo! Groups Links
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>__________________________________________________________
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>Ken Stone sasami@... otherunicorn@...
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>Modular Synth PCBs for sale <http://www.cgs.synth.net/>
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>Australian Miniature Horses & Ponies <http://www.blaze.net.au/~sasami/>
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>------------------------------------
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>The CGS Modular Synth home page: http://www.cgs.synth.net/
>Yahoo! Groups Links
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>

_______________________________________________________________________
Ken Stone sasami@... otherunicorn@...
Modular Synth PCBs for sale <http://www.cgs.synth.net/>
Australian Miniature Horses & Ponies <http://www.blaze.net.au/~sasami/>