warrenbrayshaw - Thanks ! indeed the article is very close to what I was searching. It seems that the peak sensitivity is around 370 nm and some resists are better at 405nm. I have found on a forum about using laser diodes from BlueRay players that they have achieved 60mW and more (depending a lot on optics used). In order to see how much time is needed to LDI an pcb we must see how much time should be exposed. Also on net I have seen that various photoresists and soldermasks needs about 100 mJ/cm2 exposure (I have seen some with 10mj and some with 200mj). Considering such a laser diode focused on a 0.1 mm diameter spot (that's other issue because a laser diode doesn't generate a circle spot) means = 3.14*(0.05)^2 = 0.00785 mm2 =~ 0.008mm2=0.000008cm2=8*10-5 cm2 100mJ/cm2 means equivalent 0.008mj/0.008mm2 0.008mj means 0.008mW-Second. the blueray diode has 60mW this would mean that it could "expose" 7500 spot's per second. a pcb of 320mm wide would be exposed with a speed of 0.2mm per second if the pcb is 320mm long it would take 1600 seconds ~ 27 minutes. A higher sensitivity resist would reduce the time. If someone could tell me if I am wrong or what could go wrong in this calculation please don't hesitate to contribute. Until now I don't know if it is possible to focus that diode to 0.1mm2. In disc readers the track width it's more narrower. Regards, Daniel --- In Homebrew_PCBs@yahoogroups.com, "warrenbrayshaw" <warrenbrayshaw@...> wrote: > > The following article may be of interest > http://www.circuitree.com/Articles/Column/18623649067d7010VgnVCM100000f932a8c0____ >
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Re: photoresist sensibility chart ref UV wavelength - PCB LDI using a PS3 diode
2008-06-13 by dandumit
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