Doepfer

If it's like the A-133, I find the 'zero' point to be very small. Same with the Polarizing mixer.

Neil

Sent from my iPhone

> On 5 Feb 2015, at 03:14, raulpena1974@yahoo.com [Doepfer_a100] <Doepfer_a100@yahoogroups.com> wrote:
> 
> Hello. I am doing a series on the A106-5. I read that the CV2 is a polarized input so around 12 o' clock the cv input is at zero, at +5 it is at fully positive input, and at -5 it is an inverted version of the cv input.
> 
> As long as I understand this correctly, at zero I should have no cv but when I input an envelope it does affect the cutoff a slight amount.
> 
> Can anyone confirm this behavior or explain if I am misunderstanding something?
> 
> 
> 
> Thanks for any help.
> 
> 
> 
> Raul
> 
>