> I agree with Austin. Tell us precisely what information is > missing. Don't speak vaguely about the "curves" because we know what > the response curve is of the color dyes used in the film. So we > know exactly how much to compensate the density by for any color. > Or put another way: because we know the shape of the film's response > curves there is only one unique point on the spectrum that will > produce a given density in all three dyes. So what's missing? > > You say that other people here understand you, but I don't see them > jumping in to clarify what you're saying. I think I need to weigh in again. Perhaps no one read my previous post. *I* understand Anthony, at least on this point: It is a basic mathematical fact that the process of binning is *not* reversible under almost all circumstances. Let's say that we have a spectral input of amplitude A(F), where F is the frequency. Let's take two simple response functions (the same applies to three, but I the extra lines clutter things up), r(F) and g(F). If we take two binning functions to collect r and g... R = integral over all F of (A(F)*r(F)) G = integral over all F of (A(F)*g(F)) Look at those last two equations. If I give you the result of the integral (the R value, for instance) and the r(F) response function of the filter/CCD combination, can you tell me what the input A(F) is? Answer: for all but the most trivial A(F) and r(F), no. For an arbitrary A(F), never. More simply: if you know the exact spectral response of, say, the red element of a CCD sensor, and I tell you I got a red value of 130, can you tell me the original spectral input? Answer: no. -- Jon Dubovsky ( entropy@... )
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Re: [Digital BW] Digital, film, scanning comparisons
2003-05-28 by Jon Dubovsky
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