Peter writes: > Why should this be so hard? I've explained this several times. Apparently I lack the necessary talent to make the explanation understandable. > Every black and white film has a characteristic > response curve, and that curve can be characterized > for R, G, and B ... No, it cannot. The curve is just that: a curve. The RGB values are just three numbers--equivalent to three straight lines of different heights in the spectrum. All the rest of the curve between those three lines is lost when a picture is taken in color. Because of this, the original curve of the original scene CANNOT be recreated from the RGB values. And since the original curve of the original scene MUST be recreated in order to proper render a scene in B&W based on the sensitivity curves of a black and white film, it is impossible to recreate the look of a scene capture in one way with the look of a scene captured in another way. The rule is much more general than this, in fact. It is impossible to translate any scene represented as a single set of monochrome values or as a set of R,G,B values into any other scene represented in the same way, because you MUST HAVE the original curves of the original scene in order to effect the transformation, and you cannot get these from just one number, or even from just three numbers. Additionally, the rule applies indifferently to color film and B&W film, and to color electronic sensors and B&W electronic sensors. > So if you start off with a wide-latitude > color film, like Portra, what limitations > do you bump up against trying to simulate > a given B+W film? See above. Portra produces a triplet of RGB values based on its own unique sensitivity curve. Once the film has done this, the original spectral characteristics of the original scene are lost. To create a rendering that matches what some other film would have produced, you must have the original spectrum of the original scene; three numbers won't do. > It seems like all you have to do is compute > a scalar from your source (color film) response > curve to your target (B+W) response curve for > each intensity level. But you no longer have each intensity level. You have only three levels. Everything else in between is lost. I've already provided an example. Let me try again. You have a special film (or a special filtered CCD) that is sensitive only to the yellow light of low-pressure sodium-vapor lamps. You take a picture of a scene lit with these lamps in some areas, and lit with a blend of red and green light in other areas. You then take the same picture using an ordinary color film or color CCD. What will you get? On the special yellow-sensitive film, the areas lit by LPS lamps will appear bright, and all other areas will appear dark. On the color film, however, all areas will appear equally bright. There is _no way_ to convert the RGB image from the color film in a way that will duplicate the results you got from the yellow-sensitive film, because the important information on the spectral distribution of the original light is gone. > What would NOT be described by that curve? See above. This rule applies even to color-to-color transformations. You cannot convert Portra to make it look just like Velvia, because part of the spectral information on the original scene is lost and cannot be reconstructed to make the transformation.
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Re: [Digital BW] Digital, film, scanning comparisons
2003-05-22 by Anthony Atkielski
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