RE: [AVR-Chat] Re: A little off topic, but PSU question....
2005-05-23 by Claxton, Dean J
Thanks Graham - that was some excellent information. I was a bit of a chicken and finally decided to open the screen to check for voltage regulators - seems ok with the 15V so far. Many thanks again though for your feedback on this - you may have even saved my life. Regards Dean Claxton
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-----Original Message----- From: AVR-Chat@yahoogroups.com [mailto:AVR-Chat@yahoogroups.com] On Behalf Of Graham Davies Sent: Saturday, 21 May 2005 3:37 AM To: AVR-Chat@yahoogroups.com Subject: [AVR-Chat] Re: A little off topic, but PSU question.... --- In AVR-Chat@yahoogroups.com, "Claxton, Dean J" <dean.j.claxton@t...> wrote: > ... There is a current mode PWM > chip on ... the board - M62281FP > ... adjust the output voltage > ... by playing ... What you've probably got here is something like the application circuit at the end of your data sheet. You need to know first of all that there are voltages in here that are way more hazardous than what comes out of your power outlet. Even if you've had a jolt from 110 volts AC, do not assume you will survive electrocution by the higher DC voltages inside this power supply. Don't touch anything while it's on. Plug it into its load and wait for it to discharge even after you've turned it off and disconnected it from the outlet before you touch it. Wear safety glasses. I'm serious. What you need to find is the circuit that senses the output voltage and feeds it back to the chip. Look for the optoisolator and the voltage reference shown at the bottom right of the application circuit. If there are two optoisolators, the one connected to CT(OVP) is over- voltage protection. It's the one connected to EA OUT that you want. Trace this part of the circuit and draw out the schematic. Assuming it looks like the application circuit, what you want to do is to make small adjustments to the ratio of the two resistors at the right that form a voltage divider across the power supply output. To reduce the output by 10%, try putting a resistor in parallel with the upper of these two that is ten times the value of the one that's already there. Hands off, stand back, safety glasses on and see what you get. Power off, disconnect, discharge and adjust accordingly. Don't go far from the original design voltage. You're playing with the voltage at the VCC pin of the chip as well. Graham (no liability accepted). Yahoo! Groups Links