I don't see why I need gain. A MIDI to CV converter (ala MPU101) can
only spit out 1v/oct. That means the Multimoog which has a response
of .98v/oct would be sharp when played from a 1v/oct source. Right?
If this is correct, what type of resistor network do I need to come
up with that will give me a very tight tolerance? A simple votage
divider probably won't be accurate enough. Any suggestions?
-Cary
>From: "Paul Schreiber" <synth1@...>
>
>Because you need ∗gain∗ to go "that direction". The gain needed is 1/.98
>
>Paul S.
>
>>From: Cary Roberts <Cary.Roberts@...>
>>
>>Since I'm no longer on DIY, can anyone suggest another way to accomplish
>>1v/oct to .98v/oct conversion besides:
>>
>>http://machines.hyperreal.org/manufacturers/Moog/schematics/moogfix.jpg
>>
>>I was thinking of a voltage divider network, but I don't think I could
>>get resistors of high enough tolerance. Any other ideas?
>>
>>-Cary