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Subject: Re: [motm] MOTM-510 functionality

From: "Paul Schreiber" <synth1@...>
Date: 2005-01-04

> Can someone explain the controls and relation to the math for
> the 510? I know the transfer function is Vx∗(Vy/Vz)^m. What
> exactly is m? Is this the switch? If so then are the three
> preselects 1/2, 1, and 2?

m is the exponent of the equation. The rotary switch selects the ∗range∗ of m.
In ROOT, m is <1, in UNITY, m = 1 and in POWER, m is >1.

The (warp) FACTOR knob them varies m over a small range for ROOT and POWER
settings.

>
> What is exactly is warp doing. It looks like it's just adding
> a DC offset to the AC. How is this different than the offset?
>

The WARP pots add a DC voltage, which in the equation is a ∗constant∗. This is
also true of the associated OFFSET jacks. So, it's not 'different' except you
can WARP without applying any inputs.

Best results are usually with the audio to the 'warped' into the Y IN jack, such
that 'term' is the one that is exponentiated.

Paul S.