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| Your switch will use four of those points on the pcb: +V ground a0 a1 Hm, a 2-pole 5-position...so you should have two poles and ten positions total (five for each pole). If so, you will only be using 8 of those positions (four for each pole). Match up each pole with the first four switching points for that pole. For example: i used a 2-pole 6-position switch (2 poles in the center and 12 positions on the outside). The positions were labeled 1-12. I used positions 1, 2, 3, 4 for pole 1 and positions 7, 8, 9, 10 for pole 2. So, when my switch was in the following positions A/B/C/D, where A 3LP B 2LP/1HP C 1LP/2HP D 3HP ...then A :: pole 1 > 1 :: pole 2 > 7 B :: pole 1 > 2 :: pole 2 > 8 C :: pole 1 > 3 :: pole 2 > 9 D :: pole 1 > 4 :: pole 2 > 10 (positions 5, 6 are unused, so lugs 5, 6, 11, 12 left alone) Here's how I made my connections: a0 -> pole1 a1 -> pole2 strapped: ground -> 1, 3, 7, 8 +V -> 2, 4, 9, 10 After strapping the points on the switch, I just ran one wire for +V and one wire for ground back to the PCB. ∗REMEMBER the preceeding example was for my switch. If you have a five-position switch these will be different...probably something like: A :: pole 1 > 1 :: pole 2 > 6 B :: pole 1 > 2 :: pole 2 > 7 C :: pole 1 > 3 :: pole 2 > 8 D :: pole 1 > 4 :: pole 2 > 9 Use your continuity checker on your DMM to make sure your results match these before you proceed. If this is correct, then... a0 -> pole1 a1 -> pole2 strapped: ground -> 1, 3, 6, 7 +V -> 2, 4, 8, 9 (position 5 is unused, so lugs 5 and 10 will be left alone.) Does this make sense? --- On Thu, 8/7/08, adaaxs <wonggster@...> wrote:From: adaaxs <wonggster@...> |