Archive of the former Yahoo!Groups mailing list: Homebrew PCBs

ok, time for maths.

according to a formula i found on the web a 50mm dia tube spinning at
1000rpm experiences 274m/s^2 or 28g on the inside edge.
so if there is, say 1cm high water over 1cm^2 that weighs 1g it should
produce about 28g of pressure on the wall.
1 bar is 1kg per square cm, so the pressure created by the spinning tube
is .... nothing?

According to my calculations one would need around 6000rpm to create 1bar.

HELP my maths is usually FAULTY.

Please, someone with some grasp of simple maths, do a rough calcuation and
tell me that my result is wrong and what it should be.

It would be very important to get that about right, otherwise i do a lot
of experimenting with the nozzles for nothing.
(my plan is to use compressed air to drive water through the nozzles in a
water-filled tube because i can conveniently set compressed air to 1bar
with the regulator. But i must be sure i can reach 1 bar with rotating the
tube. thanks.)


ST