I usually print mirror image for the "top", and normal for the bottom
- which already has text and stuff backwards.
But I've almost always done 1-layer top-only boards, so I can only be
trusted for the "top"
Obviously the TT process inherently mirrors when you iron on. If you
print it, turn the printed side away from you and look through the
paper with a bright light behind it, and what you see looks wrong,
then don't transfer it and you've only wased a sheet of paper.
PG
On 15/09/2009, at 3:34 PM, Harvey White wrote:
> On Tue, 15 Sep 2009 09:43:38 +0530, you wrote:
>
> > Hi
> >
> >I use Tina for all my simulations and work. It also allows me to
> create my
> >PCB's
> >
> >Being small time I would use toner transfer method for my work..
> > This is where my confusion starts.
> >
> >To better explain my problem I have uploaded two files at the
> location
> >http://tech.groups.yahoo.com/group/Homebrew_PCBs/files/First_PCB/
> >
> >The first file is InvAmp.Gif, this is the image of the PCB I see
> when it is
> >auto generated.
> >
> >The next file is InvAmp.pdf which is the print I will get and is a
> mirror
> >image.
> >
> The reversed image will transfer correctly to a board. All toner
> transfer layers when printed must be mirror images. You should not be
> able to read the print directly.
>
> Look at the diagram through the paper when held up to light. The
> toner side should be facing the light. That toner will be transferred
> to the board as you see it through the paper. At this point, you
> should be able to read the letters.
>
> >I think I am not suppose to use the mirror image for the work when
> I am
> >using toner transfer or am I thinking wrong ??
>
> You do use the mirror image. Try the experiment with a piece of
> paper. Try to transfer the image from the paper (cheap paper, scrap
> of board) to the board. You should see the image properly.
>
> In some programs, you may or may not automatically print the bottom
> layer reversed, you do, this is good. It saves a step.
>
> Harvey
>
> >
> >This may be very silly but I am just not sure.
> >
> >My actual circut is quite different but I just used this simple
> inverting
> >amp of an opamp to demonstrate my query.
> >
> >Thanks
> >Regards
> >--
> >Gaurav Verma
> >Email - Gaurav.Verma.MCA@...
> >Phone - 9910732960
>