<html><head><meta http-equiv="content-type" content="text/html; charset=utf-8"></head><body dir="auto"><div dir="ltr">Is there a simple way to do a similar circuit but reversed, like for a dry/wet pot? </div><div dir="ltr"><br><blockquote type="cite">On Dec 15, 2020, at 12:38 PM, David G Dixon <dixon@mail.ubc.ca> wrote:<br><br></blockquote></div><blockquote type="cite"><div dir="ltr">
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<div><font size="2" face="Arial"><span class="893392018-15122020">Hey
Team,</span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020">I've been thinking
about this panning thing, and I came up with the following very simple pot-based
panning circuit:</span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020"><div><SimplePanner.png></div></span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020">The gain responses
of this circuit are shown below, and compared with sin and cos
responses:</span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020"><div><PanPlot.png></div></span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020">I believe that I can
create a voltage-controlled version of this simple pot panning circuit fairly
easily by replacing the pot with a pair of modified Irwin 2164 circuits. I
did this for the Morphing LFO.</span></font></div>
<div><font size="2" face="Arial"><span class="893392018-15122020"></span></font> </div>
<div><font size="2" face="Arial"><span class="893392018-15122020">Would this response
suffice as an "equal power" panner?</span></font></div>
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