<html><head><style type="text/css"><!-- DIV {margin:0px;} --></style></head><body><div style="font-size: 13px;color: rgb(0, 0, 0);font-family: arial, sans-serif;">Are you measuring AC or DC volts?<div><br></div><div>2.4VDC might be an OK reading for a 5VAC square wave, depending on how your meter integrates it.<br><div><br></div><div><blockquote style="padding-left: 5px; margin-left: 0px; border-left: #0000ff 2px solid; font-weight: normal; font-style: normal; text-decoration: none; font-size: 10pt; font-family: arial,sans-serif; color: black;">-----Original Message-----
<br>From: Elain Klopke <functionofform@gmail.com>
<br>Sent: Apr 4, 2017 12:43 PM
<br>To: *SYNTH DIY <synth-diy@synth-diy.org>
<br>Subject: [sdiy] breadboard woes
<br><br><div dir="ltr">So I was trying to get a reading on my breadboard to see how much voltage was lost between the input of three passive low pass filters in series and the output. <div><br></div><div>My measurements between ground and:</div><div>positive supply: 5.06 V</div><div>Output from chip: 2.4 V (was expecting 5 V because digital square wave)<br></div><div>junction of first and second resistor: 2.4 V</div><div>junction between second and third resistor: 2.4 V</div><div>after third resistor: 2.4 V ....</div><div><br></div><div>All resistors measured at 5.07 kOhms. I'm not sure what's going on. Is my breadboard messed up somehow or am I missing something fundamental about electronics?</div></div>
</synth-diy@synth-diy.org></functionofform@gmail.com></blockquote></div></div></div></body></html>