<div id="RTEContent">One other problem might be that you are using two stages<br> in linear mode. These will get hotter than normal. Make sure it<br> does not run TOO hot. Its probably Ok.<br> <br> The resistors do not limit this power... it flows from N to P channel device<br> which are both 'half on'. It will be worst with no signal input<br> <br> H^) harry<br><br><b><i>Seb Francis <seb@burnit.co.uk></i></b> wrote:<blockquote class="replbq" style="border-left: 2px solid rgb(16, 16, 255); margin-left: 5px; padding-left: 5px;"> René Schmitz wrote:<br><br>> Hi Harry, Seb and all,<br>><br>> Harry Bissell Jr wrote:<br>><br>>> with a 10K resistor in the inout you might be over the edge. I'd be<br>>> concerned. You might want to use shottky clamp diodes instead<br>>> of allowinng the CMOS input diodes to clip.<br>><br>><br>> A few mA into the diodes won't hurt. There is a parasitic thyristor <br>> which might fire when a!
certain
current is exceeded. No need for extra <br>> shottkys IMO, I'd rather make that resistor a little larger.<br>> Ok, this is stretching the ratings in the datasheet a little, but does <br>> work.<br>><br>> Btw, this sort of overdrive is explicitly allowed for the 4049 and <br>> 4050, to be able to do a 15V to 5V crossvolt conversion. Check the <br>> datasheet on these.<br>><br> From what I can tell from the datasheet the 4049 doesn't have the <br>protection diode from input to VDD. Instead it has a 30V zener from <br>VSS to input. So there's still no clue as to the max current that can <br>flow through the protection diode(s) without damage.<br><br>But you have encouraged me just to try a larger input resistor (e.g. <br>100K). Perhaps I should leave it running for some time with a <br>full-scale-input and see if any damage occurs (i.e. if it stops clipping <br>at the input I'll know I've burnt out the diode)<br><br>Seb<br><br><br></blockquote><br><!
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