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<DIV><FONT face=Arial size=2>Eric,</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Transformers are pretty straight
forward:</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Except for small losses due to; eddy currents in
the core, hysteresis, copper resistance, flux leakage, transformers are
efficient.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>The voltage ratio is the same as the turns
ratio</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>N-in : N-out</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>V-in : V-out</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Power out equals power in minus the losses
mentioned above.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>P-in = P-out</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Current ratio is the inverse of the turns ratio.
Input current is a reflection of the demand on the output.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>I-out : I-in</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>The impedance ratio is the square of the turns
ratio.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>Z-in = Z-out ( N-in / N-out)^2</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV><FONT face=Arial size=2>I hope this helps.</FONT></DIV>
<DIV><FONT face=Arial size=2></FONT> </DIV>
<DIV>Take care,<BR>John</DIV>
<DIV> </DIV>
<DIV>Pacific Northwest Synth Meeting September 25, 2004</DIV>
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style="PADDING-RIGHT: 0px; PADDING-LEFT: 5px; MARGIN-LEFT: 5px; BORDER-LEFT: #000000 2px solid; MARGIN-RIGHT: 0px">
<DIV style="FONT: 10pt arial">----- Original Message ----- </DIV>
<DIV
style="BACKGROUND: #e4e4e4; FONT: 10pt arial; font-color: black"><B>From:</B>
<A title=Robotboy8@aol.com
href="mailto:Robotboy8@aol.com">Robotboy8@aol.com</A> </DIV>
<DIV style="FONT: 10pt arial"><B>To:</B> <A title=synth-diy@dropmix.xs4all.nl
href="mailto:synth-diy@dropmix.xs4all.nl">synth-diy@dropmix.xs4all.nl</A>
</DIV>
<DIV style="FONT: 10pt arial"><B>Sent:</B> Tuesday, September 21, 2004 4:27
PM</DIV>
<DIV style="FONT: 10pt arial"><B>Subject:</B> [sdiy] Transformer
confusion</DIV>
<DIV><BR></DIV><FONT face=arial,helvetica><FONT lang=0 face=Arial size=2
FAMILY="SANSSERIF" PTSIZE="10">Alright. I was thinking about
transformers today, and have come up with a lossless passive amplifier!
(Okay, I know this wouldn't work, elsewise it would be a miracle device that
everyone would have heard of... but I'm trying to figure out WHY
not).<BR><BR>So. A step-up transformer - two magnetic cores with wires,
yadda yadda - increases voltage, but you pay for that increase with a decrease
in wattage. (right?) So far we have the xformer with less windings
on the left and the one with more on the right. Now get another one
that's identical to the one on the right (more windings than the one on the
left) and set it furthest left (so you have more-wound, less-wound, more-wound
in that order). That one will act identically to the one on the right
(correct?) but be 180 degrees out of phase (correct?). But what if you
ran that through an inverter and combined that signal with the output of the
other more-wound inductor, wouldn't you have a higher signal (in voltage AND
wattage) than what you started with?<BR><BR>I know it doesn't work this
way. What I'm wondering is why it
doesn't.<BR> -eric</FONT>
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