[sdiy] How is the feedback loop of the exponential converter analysed?
Spiros Makris
spirosmakris92 at gmail.com
Wed Jan 29 09:33:29 CET 2020
Hello,
Thanks for stepping in David! I'm familiar with stability theory, PM, GM
etc but on common linear amplifiers or control loops. My problem is how to
approach this circuit analytically so i can establish tradeoffs and pick
components (the opamp and capacitor, basically), with a method other than
"47p looks good".
So, René this essentially means that to get a higher bandwidth for the
converter (CV to Iout) I will need a faster opamp?
Thanks,
Spiros
On Tue, Jan 28, 2020 at 8:30 PM René Schmitz <synth at schmitzbits.de> wrote:
> On 28.01.2020 18:53, David Manley wrote:
> > Hi Spiro,
> >
> > I haven't seen a reply to your question, so I'll just point you in the
> > general direction and hope that helps. I'm sure one of the analog gurus
> > will step up and correct me. :-)
> >
> > An opamp can affect not only the gain of a signal it is processing, but
> > also its phase. If the output phase is shifted over 180 degrees, that
> > signal is feed back to the input, and the opamp has gain at that
> > frequency then it will oscillate. Look up 'gain and phase margin'.
> What happens here is that the transistor provides gain. While we are
> mainly interested in the current typically (and the current gain is
> close to 1), if we break up the loop, at the - input of the opamp, and
> look at the collector as the output, we find a bona fide born-and-bread
> common base circuit, with a voltage amplification of roughly
> R(collector)/R(emitter).
>
> That gain in the loop eats up the phase margin because the gain is in
> the order of 1000 here. An you need to overcompensate the opamp to keep
> the loop stable.
>
> In practice there are also some effects due to the various capacitances,
> of the transistor but they will likely get reduced if the collector is
> kept at a constant potential.
>
> Best,
> René
>
> --
> synth at schmitzbits.de
> http://schmitzbits.de
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