[sdiy] Polymoog resonator question

Richie Burnett rburnett at richieburnett.co.uk
Sat Oct 6 22:37:17 CEST 2018


---- Donald Tillman wrote ----

> The pot taper issue gets interesting.
> 
> An audio taper pot isn't really an exponential curve; it's two linear curves spliced together at the center.
> 
> And the Polymoog resonator uses linear pots in series with the input resistor, and the gain is proportional to the inverse of the resistance:
> 
> TFintegrator = 1 / (2400 + (1-x)10000) sC
> 
> Where x is the pot travel, 0.0 to 1.0.
> 
> And you can plot that, and it's log, on the Grapher app on a Mac, or any plotting facility, and check it out.

Shouldn't the gain vary exponentially in shape with pot position in order to get an exponential frequency response from the control that feels natural?

-Richie,



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