[sdiy] CA3046 Heater / Substrate Question
Nils Pipenbrinck
n.pipenbrinck at hilbert-space.de
Fri May 6 14:01:18 CEST 2016
On 05/06/2016 10:44 AM, Roman Sowa wrote:
> You say, Q3 base is at -1.8, but with no heating current (at start) Q3
> emmiter is at about -0.7, determined by 2 small resistors and BE
> junction of Q2. So the substrate is higher than Q3 base and all
> transistors are connected now, no substrate isolation.
> Loose the LED and it should work, but substrate will be at very low
> negative voltage now, I'm not sure if it will not degrade expo pair
> performance.
Hi Roman,
thanks, that makes sense. I'll have thoroughly think through it, but
it's clear that I messed up the substrate somehow. I just don't know
where exactly the s. hits the f.
> BTW, "better" is an enemy of "good". What is wrong with just 1
> transistor heater?
There is nothing wrong with it, but it's not ideal because the 1
transistor heater can only dissipate 300mW. The cooling of the package
takes away a big chunk of the energy we put into heating. So reaching
tuning stability is slower than it could be.
I did some measurements yesterday, measuring the Vbe drop directly while
heating with two different target temperatures. I faked a bit, left the
substrate transistor connected as usual and used one of the matched pair
transistors as my second heater:
http://torus.untergrund.net/synth/heater_65deg.png
Here I aim at 65°C. You'll see that the two transistor circuit reaches
stability after 4 seconds while the one transistor circuit needs about
100 seconds:
http://torus.untergrund.net/synth/heater_90deg.png
Here I aim at about 90°C. The two trannie method reaches stability after
half a minute while the single transistor never reaches it's target
temperature and asymptotically drifts to somewhere around 70°
I think this is a great improvement over the one transistor circuit, and
the substrate transistor is unused, so why not use it as a second heater?
Best,
Nils
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