[sdiy] LM4040 setup

[Rutger Vlek]

Ah, yes that's what I wanted to know exactly! Thanks :).

Rutger


On 26 feb 2015, at 13:57, Michael Zacherl wrote:

> 
> On 26.Feb 2015, at 13:55 , Michael Zacherl <sdiy-mz01 at blauwurf.info> wrote:
> 
>> 
>> On 26.Feb 2015, at 12:45 , Rutger Vlek <rutgervlek at gmail.com> wrote:
>> 
>>> This leads me to the question of the current demands of potentiometers. Say, I have a 10K potentiometer for filter cutoff wired between my + and -5V references, with the wiper going to a 100K-impedance inverting amplifier section. What would be the current load for the +5V and -5V reference supplies?
>> 
>> hm, not sure if I understand the problem. otherwise it be 10V / 10k = 1mA?
> 
> +/- some 10µA for the 100k load ...
> 
>