[sdiy] step response of second order filter

[Neil Johnson]

Hi Harry,

> Does the "q" of such a filter make any difference.  ie at a value of .707 I'd expect one overshoot, one undershoot, then settling.
> Higher resonance values extend this.

Simply: Q = 1/d.

So small values of Q mean high damping, large values of Q mean low damping.

> What about if the Q was less than .707 ? would the filter then be underdamped ?

Overdamped.

Cheers,
Neil
-- 
http://www.njohnson.co.uk