[sdiy] step response of second order filter

[Harry Bissell]

Hello all

in a previous thread i asked about the step response of a second order filter (SVF). The consensus was that the
step response (overshoot, undershoot, settle) was an inevitable consequence of the (2nd order) filter itself.

Does the "q" of such a filter make any difference.  ie at a value of .707 I'd expect one overshoot, one undershoot, then settling.
Higher resonance values extend this.

What about if the Q was less than .707 ? would the filter then be underdamped ?

H^) harry