[sdiy] Audio taper pots
stewpye at optusnet.com.au
Fri Aug 24 22:48:51 CEST 2012
If the attenuators (linear pots) are feeding directly into a mixer then
simply reduce the value of the summing and feedback resistors so that
the summing resistors are about 1/5 the value of the pot value. This
means that you may have to buffer the inputs before they get to the
pots, but this may be cheaper than getting two different pots. A quad op
amp is only about $0.20 and you could use a soic package to keep the
On 8/25/2012 5:45 AM, Mattias Rickardsson wrote:
> I think it's extremely important to avoid linear scales on parameters
> that are not experienced linearly - mainly since it's so easy.
> Otherwise you'll end up with something that reminds of the hopeless
> response of the volume sliders on cheap old plastic radios... where
> almost everything useful is within the first 20%. :-)
> Shunt it like Mark suggested, probably with an even smaller resistor
> (around 1/5 of the pot value). This is all you need:
> On 24 August 2012 21:30, mark verbos <mverbos at earthlink.net> wrote:
>> I think it's important, but you could use tapering resistors.
>> i.e. run a resistor from the wiper to ground that is about double the value of the pot.
>> On Aug 24, 2012, at 2:19 PM, David G Dixon wrote:
>>>> How important is it to use audio taper pots for audio
>>>> attenuators? I have a mixer design that needs linear pots for
>>>> panning. Can I use linear pots for the attenuators? It would
>>>> mean stocking just one pot, and at 1000 minimum quantity I'd
>>>> like to avoid needed 2 pots.
>>> IMHO, it's not important at all. I use Linear pots on all mixer inputs, and
>>> they work very well.
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