[sdiy] ...that 1K resistor on the output

[Jerry Gray-Eskue]

If I visualize this correctly, it should work as expected.

In the normal signal level range the  Zener diode string should be "off" 
until the forward drop and Zener breakdown voltage is meet or exceeded so 
the bleed resistor is still needed.

----- Original Message ----- 
From: "David G. Dixon" <dixon at interchange.ubc.ca>
To: "'Justin Owen'" <juzowen at googlemail.com>
Cc: "'SDIY List'" <synth-diy at dropmix.xs4all.nl>
Sent: Thursday, January 27, 2011 12:51 PM
Subject: Re: [sdiy] ...that 1K resistor on the output


>> If I'm using Zener/clipping diodes on Inputs/Outputs - i.e. Anode to 
>> Anode
>> in anti-parallel with Cathode to Ground (what a mouthfull?!) - is adding
>> the bleed resistor to Ground - which would put it in parallel with the 
>> two
>> clipping diodes - still going to let both the resistor and the diodes do
>> their jobs?
>
> It's actually "anti-series".  Regular diodes would be "anti-parallel".
>
> Anyway, the bleed resistor is there to drain off DC which has no other
> escape route.  I should think that the zeners would accomplish this just 
> as
> well.  HICBW*
>
> *HICBW = "however I could be wrong"
>
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