[sdiy] Antilog/Exponential converter help

Ian Fritz ijfritz at comcast.net
Tue Dec 27 22:22:01 CET 2011


Justin --

R1 provides a standing current of 12uA.  This is the current at zero 
(total) input voltage.  It is also close to the max control current you 
want. So your input  voltage range need to be from around zero volts on 
down. Thus your fixed bias needs to be -2.5V.

Ian








At 12:23 PM 12/27/2011, Justin Owen wrote:
>Hey all,
>
>I'm trying to set up a Linear to Exponential/Antilog current source to 
>drive a transistor differential amp (that has a linear response).
>
>http://www.sdiy.org/juz/expo_converter_03.pdf
>
>Using a Linear current mirror with an input voltage of 0 to 2.5V, 
>converted to approx. 0 to 10uA I get a nice clean linear response and 
>unity gain at the output of the differential amp from 0 V PP to approx. 10 
>V PP - so I know the differential amp is working as required.
>
>I would like to take the same control voltage of 0 to 2.5V, convert it to 
>approx. 0 - 10uA (although I can be flexible about that...) and convert 
>the output curve (Iabc) to an exponential response.
>
>So far, the schematic linked above, made up from my own research and data 
>sheets is not giving me the required response and adjusting the various 
>resistor values just seems to be shifting the linearity/gain response 
>upward/downward and not bringing me any closer to an exponential/antilog curve.
>
>One thing I noticed is the need for a -VRef offset IC2A that I didn't need 
>on the Linear source - apart from that and the shape of the curve it works 
>well!
>
>Can anyone offer any advice on component values I should be looking at, 
>things I could check/change, what I might be doing wrong?
>
>Thanks in advance.
>
>Justin
>
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