[sdiy] Quick C query

[Tom Wiltshire]

On 21 Nov 2010, at 18:05, Steff wrote:

> On 21 November 2010 17:45, cheater cheater <cheater00 at gmail.com> wrote:
>> 
>>> if(flags == (BLARP | BAR)) { /* do stuff here */ }
>> 
>> I think you mean:
>> 
>> if(flags & (A | B) == (A | B)) {
>>  ...
>> }

I've seen this written as:

	if (flags & (A | B)) {
	 ...
	}

Which would be the following for a single flag:

	if (flags & mask) {
	 ...
	}

There's no need for the part with the "==(etc)", since C is just looking for a non-zero result to indicate true (simply processor zero flag clear, I hope).

Or have I got the stick by the sticky end?

T.