[sdiy] CV inputs with bipolar "amount" knobs

[Mattias Rickardsson]

On 25 July 2010 04:06, cheater cheater <cheater00 at gmail.com> wrote:
>
> But if you want the curve to be less steep around the center you want
> an exponential or even better an nth power response such as x^3. A
> logarithmic response makes it more difficult to zero in on the center.

Yes, a "log" pot is exponential. :-)

>> Perhaps the limitations of the first inverter such as slew rate and HF
>> roll-off would not occur much in the second inverter, removing
>> problems with spikes etc passing through in the null point?
>
> No, their frequency responses would accumulate. In the end a simple
> model of the situation looks like this: every partial of the signal...

Perhaps I shouldn't have mentioned frequencies, I was thinking
primarily of slew rate. If "too quick" changes are slewed out in the
first inverter, they can pass the second inverter quite unaltered. The
positive and negative versions of the signal taken after the first and
second inverter would then be more alike than if taking them before
and after the first inverter.

Before and After Science,

/mr