[sdiy] Using SSM2164 in stereo

[cheater cheater]

That's a very good explanation - thanks, Walker!

D.

On Thu, Jan 21, 2010 at 09:15, Walker Shurlds <walkershurlds at gmail.com> wrote:
> On Thu, 21 Jan 2010 08:15:38 +0100
> cheater cheater <cheater00 at gmail.com> wrote:
>
>> > The electrons lose potential, but the same number of them flow.
>>
>> But an electric potential of a conductor is defined by the amount of
>> electrons in that conductor. How do electrons 'lose potential'?
>
> Potential of an electron has to do with its energy state, compared to
> the default energy state.  Voltage is the average of these energy
> states for all electrons in the conductor.  At one end of a voltage
> source, all of the electrons are in a higher energy state, and to do
> work, they move to a lower energy state, at which point they arrive at
> the other end of the voltage source.
>
>
>> And if potential is lost (= electrons are lost) how are we conserving
>> the current across the resistor?
>
> No electrons are ever lost.  As electrons do work, they lose potential,
> the same way that when you roll a ball down a hill it loses it's
> potential energy, but the ball never vanishes.
>
>> I understand the current on the output of the current source stays the
>> same. But that does not imply that the current at 'the end' stays the
>> same, does it? I thought current sources were infinite charge pumps
>> that terminated in ideal sinks. That just might be me, though, so
>> correct me if I'm wrong.
>
> I don't know exactly what you're saying.  The current going into
> anything is the same as the current going out of it no matter what.
> Ideal current sources have a constant current, therefore sticking a
> resistor in front of it results in a voltage.
>
> If you put a current source right up to a high-impedance input, the
> result is going to be constant current * high impedance = high voltage
> = bad.
>
> Hope this helps,
> Walker
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