[sdiy] Using SSM2164 in stereo

cheater cheater cheater00 at gmail.com
Thu Jan 21 08:15:38 CET 2010


> The electrons lose potential, but the same number of them flow.

But an electric potential of a conductor is defined by the amount of
electrons in that conductor. How do electrons 'lose potential'?

And if potential is lost (= electrons are lost) how are we conserving
the current across the resistor?

I understand the current on the output of the current source stays the
same. But that does not imply that the current at 'the end' stays the
same, does it? I thought current sources were infinite charge pumps
that terminated in ideal sinks. That just might be me, though, so
correct me if I'm wrong.

D.

On Thu, Jan 21, 2010 at 07:28, David G. Dixon <dixon at interchange.ubc.ca> wrote:
>> But a true virtual current source does not need to be limited, since
>> it is going to supply a constant (or controlled) current, right?
>
> Quite right.  And it would supply that current regardless of the resistor
> appended to it, unless of course the resistor pushed the source voltage
> right to the rail, in which case one would exceed the "compliance" of the
> current source.  Probably another reason not to put one on.
>
>> Don't resistors only limit current from voltage sources?
>
> Yes.
>
>> With current
>> sources, we have U = IR, so that we're 'limiting' voltage. I
>> understand that the losses in current would be due to the resistor
>> heating up which is not a very efficient way of limiting current.
>
> Hot resistors don't lose current.  They lose energy in the form of heat.
> The electrons lose potential, but the same number of them flow.
>
>




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