AW: [sdiy] AD/DA schematics? quantizers,etc

[Jerry Gray-Eskue]

<<mean by "transition right on the note"?
> The note C3 should be exactly 0 V. The note C#3 should be 0.83333 Volts.
>>

Yes this is most of it, the other thing is that Where the voltage changes
relative to the input voltage is important to prevent the output voltage
from varying due to Bit Toggle.

For example if note C3 is exactly 0 V and your Output step voltage is
0.83333 Volts the Input voltage range that gives you the C3 output should be
+- 1/2 step or -0.41666...Volts to +0.41666...Volts.
This is what I mean by Centered on the Step.


-----Original Message-----
From: synth-diy-bounces at dropmix.xs4all.nl
[mailto:synth-diy-bounces at dropmix.xs4all.nl]On Behalf Of
Matthias.Herrmann at jeppesen.com
Sent: Friday, May 15, 2009 4:09 AM
To: synth-diy at dropmix.xs4all.nl
Subject: Re: AW: [sdiy] AD/DA schematics? quantizers,etc


synth-diy-bounces at dropmix.xs4all.nl wrote on 05/15/2009 10:57:41 AM:
> Hello Matthias
>
> > i am not quite sure if i understand (due to my poor english). what do
you
> > mean by "transition right on the note"?
> The note C3 should be exactly 0 V. The note C#3 should be 0.83333 Volts.

> The note D3 should be 1.66666 Volts. The note H2 should be -0.83333
> Volts, and so on....
>
> While you only concentrated on the relative step-width, he focuses the
> absolute voltage. But this can be handled easily by an follwing voltage
> offset.

i see!
thanks for clarification.

cheers,
matthias
___
www.fonitronik.de

>
> Florian
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