[sdiy] Analysis of Buchla 259 amplitude modulation circuit
Aaron Lanterman
lanterma at ece.gatech.edu
Wed Jun 10 08:15:38 CEST 2009
Because of an apparent masochistic streak, I'm currently trying to
decipher the Buchla 259. Right now I'm checking out the amplitude
modulation circuitry, which is essentially the last thing that gets
applied. Gaze here:
http://rubidium.dyndns.org/~magnus/synths/companies/buchla/Buchla_2590_4_200.jpg
I'm looking primarily in the middle - there's a circuit with a dual
vactrol, with a 0-5V CV from the modulation oscillator coming in,
which I will call vi.
Denote the voltage at the junction of R272 and 273 as v*.
_If_ I assume "golden op amp rules" (this is iffy - see below), I get
an equation from the currents summing at pin 5 of IC 34 (the +
terminal of the op amp):
vi/49.9K + v*/20K = 15V/75K,
and for the v* node, I get
v*/(2K || R) = (15V - v*) / 30.1K, where R is the resistance of the
vactrol.
After a veritable truckload of algebra, I get
R = 12Kohm * (10V - vi)/(5V + vi)
Fascinating! The vi determines the resistance R.
Let us define a "gain" from pin 1 of IC 33 to pin 7 of IC 3. This gain
is given by
gain = -10K/115K + (1+10K/15K) * R / (R_trim+R),
where 10K < R_trim < 15K depending on how the pot is set.
Taking R_trim = 10K and plotting the gain in FreeMat (no, I didn't
slog through more algebra), the result is remarkable - it looks like
straight downward sloping lie going from 0.5 at vi = 0 volts to -0.04
at vi = 5 volts. If I crank R_trim to 15K, I get something running
from 0.36 to -0.19.
There's a second dual vactrol in the at the right, which controls how
much of this AM signal gets mixed with an inverted version of the
original signal, presumably to be able to crossfade from the original
signal to a pure "ring mod" type sound if you get the original and
inverted versions to cancel with at a high "index."
Two questions:
1) Let's talk about golden op amp rules. For those to hold, we need
"negative feedback." First of all, the - terminal is grounded instead
of the positive terminal, so that's suspicious - but then, this is
clearly not being used like a comparator. Secondly, there's not any
direct electrical connection from the output of the op amp back to the
input.
Yet, the output of the op amp does effect the input through the LED/
resistor combination. I suspect the underlying feedback mechanism that
I'm presuming is somehow inherentlly "negative," hence the need to
back to the positive terminal.
The balanced modulator in the Music Easel has some similar kinds of
craziness. And I've breadboarded that, and it works. (And some PCBs
for it are on their way here from China now, but that's another story).
Am I on target? Anyone want to take a stab at making my handwaving
more rigorous - rather than vigorous? ;)
2) Assuming all my analysis above works - and the results do make
sense, it seems to do what it's supposed to - HOW THE HECK DID HE
THINK OF THAT CIRCUIT?
- Aaron
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