[sdiy] How do old electrolytics go bad?
Steve Carter
steve at willacy.co.uk
Mon Feb 9 10:24:15 CET 2009
Count me in on that Bob! I've done the same thing over the many
decades without any problems although some engineers regard it as
being more than a little uncouth! I remember shorting a capacitor
that produced an arc welding sound leaving the screwdriver unharmed
but the aluminium rivet securing one of the terminals was arcing to
its terminal in a big way. The high resistance at that junction, due
to corrosion that couldn't be seen, was just waiting to become a
problem - after that I was convinced it was good practice in some cases.
I must admit, nowadays I usually incorporate a bleed resistor in my
valve designs so that it goes safe pretty quickly after switch-off.
Steve
On 9 Feb 2009, at 05:52, Bob Weigel wrote:
> You never do it in huge capacitors of course. For one thing they'll
> blow the end of your screwdriver off and send fragments flying that
> might hit you in the eye :-) But on ones typically found in your
> garden variety guitar amps ( eg. 70uF 350V, 22uF 500V etc.) you can
> safely discharge their total energy without damage. Years of
> experience has taught me this...(not to mention the calculations on
> the material heating if the connections are within normal parameters
> are not that hard to do. And I've done those kinds of calculations
> in the past. One knows the amount of potential energy is just the
> charge times voltage. Q=CV so for example the 500V 20uF say has
> 10mC of charge on it. UNLESS something is wrong with the
> connection /wire you should have about .01ohm or less there for
> sure. If there IS something wrong..hey..now's the time to find out
> baby! It's in my shop!! :-) But if not the energy I believe should
> be 10mC x .01ohm ^2 = 10^-6 joules WERE it a perfectly sparkless
> short. That's why us all pro capacitor bangers use dirty
> screwdrivers!! :-) That way the lion's share of the energy is
> absorbed in the higher resistance surface of the screwdriver rather
> than in the capacitor! But even in the worst case Aluminum has a
> heat capacity of 800 J/Kg-K and we're talking about a practical
> distribution of this heat in a unit with a strong connection over
> two lead's connection area with a practical mass of relevance in the
> area of .3G at least. So I believe that'd be 10^-6j/800x.0003kg ) =
>
> 4x10^-6 ºK
>
> Much wisdom can be achieved from doing the actual physics of an
> approximation of the situation. Questions like 'but what if I'm off
> by a factor of 100?' are returned with 'who cares?' :-) Unless I've
> really done something horribly wrong in my analysis (hey it's always
> possible..check my work) then this correlates strongly to my
> practical experience in this area. NEVER discharge power grids...
> car batteries... or very large capacitances again using a
> screwdriver because pieces might hit you. But for small caps...
> Years ago in a discussion ABOUT how to discharge them in common
> small tube amps I said 'let er rip'. But close your eyes while
> doing it I should have said just in case something flies but I think
> others had already covered that nicely :-). But on small caps I've
> done it hundreds and hundreds of times. Nobody gets hurt. And it
> doesn't wreck your capacitors. I do NOT do it on caps above a few
> thousand uF at 50V or above 100uF or so at 500V because I don't like
> to damage screwdrivers and the sound can be fairly loud :-) But
> again even at those values the calculations should make it obvious
> that nothing is really going to get damaged *unless* it's a
> capacitor with a rusty interface somewhere...in which case isn't it
> better to find out now then down the road after vibrations and a
> little more use cause it to manifest with a loud hum during thy
> performance?
>
> -Bob
>
> Oren Leavitt wrote:
>
>> The instantaneous current flow caused by a short-curcuit discharge
>> can damage (or degrade) large value electrolytics - usually by
>> breaking the point where the lead connects to the inner foil like a
>> blown fuse.
>> Some capacitors, such as photoflash capacitors, are designed with
>> heavier electrode structures for instantaneous discharge.
>> If you have to discharge a capacitor, a "soft" discharge using a
>> resistor is the preferred way.
>>
>> - Oren
>>
>> Samppa Tolvanen wrote:
>>
>>> Hi,
>>>
>>> What about a discharge using a screwdriver?
>>>
>>> Samppa
>>>
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