[sdiy] Deciphering the Buchla 259's expo converter
Aaron Lanterman
lanterma at ece.gatech.edu
Tue Feb 5 08:03:35 CET 2008
Greetings! This is Aaron Lanterman, the GaTech professor that taught a
class called "Theory and Design of Music Synthesizers" a couple of
times a couple of times during 2006.
I'm running the class again, somewhat modified, this semester, under
the name "Electronics for Music Synthesis." Alas, I don't have the
website for the class really set up yet. I will post here when I've
done so. In the meantime, I've been recording the lectures with a
cheap camcorder and posting them on blip.tv under the username
"abovenyquist." Stop by and enjoy. (It's blip.tv, not blip.tv.com - I
think you can get it from abovenyquist.blip.tv, or go to blip.tv and
search on the username abovenyquist.) You can also find lectures from
my Fall 2007 class, "Multicore and GPU Programming for Video Games,"
if your interested in that sort of thing - I've been spending many
months knee deep in things like shader programming and the Cell
processor, which is why I'd dropped out of looking at synths for a
while.
Anyway, last time I did the class, I analyzed the core of the Buchla
259 in lecture as an example of a triangle-core VCO. I talked about
the discrete OTA, the comparitor, the integrator, etc., and then
handwaved and said "look, here's the expo generator."
This time I'd like to actually do the expo generator. I'm pretty well
versed in Buchlaese by this point (and I teach Buchlaese, i.e. how to
read his schematics, to my students), but this one has me confused.
I'm looking here:
http://rubidium.dyndns.org/~magnus/synths/companies/buchla/Buchla_2590_2_200.jpg
So, I'm looking at R122, R123 and R123A. R122 is a 1K tempo, R123
appears to be 68K but it's hard to read from the schematic, and R123A
is 121K. R122 and R123 form a typical divide down ladder before the
base of an expo-converting differential pair. R123A is tied up to +15
for reasons that befuddle me - I'm not sure why you'd mix in something
here instead of mixing it in at the inverting op amp.
Anyway, I'm guessing that 121K in parallel with 1K is sufficiently
close to 1K (i.e. it's 0.99K) that I could interpret the divide down
ladder as consisting of 1K and 68K, which gives me, if I want to find
the volts per octave,
exp(-v*(1/69)/vt) = 2
and assuming a vt of 26 mv, I get
-v*(1/69) = 0.026*log(2)
v = -1.2435
The divide down ladder is fed by an inverting op amp, so I could
interpret this as being 1.2435 volts per octave. This, I suppose, is
pretty close to the 1.2 volts/octave I've heard that Buchla uses.
But then the inverting op amp is confusing me. I see an octave input -
OK, I imagine thats from some kind of rotary switch, maybe - that
comes in through a 56K input resistor, and a "freq cv" input that
comes in through a 150K resistor. In any case, the feedback resistor
is 100K - so it doesn't seem there's any way I could interpret either
input voltage as giving 1.2 volts per octave. If I saw something with
a 100K input resistor that would make more sense to me.
Can someone help me with my confusion? If I can't figure it out, I'm
going to handwave when I get to the expo converter part. (Last week I
showed how how expos work in a typical 1 volt/octave style converter,
as discussed on Rene Schmitz's website, but I wanted to do another
example of one since I didn't explain it very clearly. I off my game
that day.)
- Aaron
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